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Given #theta = (19pi) / 6# how do you find #tantheta#?

1 Answer

Jun 30, 2015

#tan((19pi)/6) = 1/sqrt(3)#

Explanation:

#theta =(19 pi)/6 = 2pi + (pi+pi/6)#

So #theta# has a reference angle of #pi/6# in quadrant 3.

#tan(theta)# is positive in quadrant 3 and
#pi/6# is a standard angle with #tan(pi/6) = 1/sqrt(3)#
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