Given $theta = (19pi) / 6$ how do you find $tantheta$ ?

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Answer 1 · 2015-06-30T11:18:14

$tan((19pi)/6) = 1/sqrt(3)$

$theta =(19 pi)/6 = 2pi + (pi+pi/6)$

So $theta$ has a reference angle of $pi/6$ in quadrant 3.

$tan(theta)$ is positive in quadrant 3 and
$pi/6$ is a standard angle with $tan(pi/6) = 1/sqrt(3)$
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Given theta = (19pi) / 6theta = (19pi) / 6 how do you find tanthetatantheta?