Given the point #P(-12/13, -5/13)#, how do you find #sintheta# and #costheta#?

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Given the point #P(-12/13, -5/13)#, how do you find #sintheta# and #costheta#?

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Answer 1 · 2018-03-06T04:09:52

#sin t = - 5/13#
#cos t = - 12/13#

Explanation:

#tan t = y/x = (- 5/13)/(-12/13) = 5/12#.
P and t are located in Quadrant 3.
#cos^2 t = 1/(1 + tan^2 t) = 1/(1 + 25/144) = 144/169#
#cos t = +- 12/13#
Since t is in Quadrant 3, therefor, cos t is negative
#cos t = - 12/13#.
#sin t = tan t.cos t = (5/12)(- 12/13) = - 5/13 #

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Given the point #P(-12/13, -5/13)#, how do you find #sintheta# and #costheta#?

1 Answer

Explanation:

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