Given #tanx=5/12, secx=13/12# to find the remaining trigonometric function?

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Given #tanx=5/12, secx=13/12# to find the remaining trigonometric function?

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Answer 1 · 2017-03-27T03:02:24

#sec x = 1/(cos x) = 13/12# --> #cos x = 12/13#
#tan x = 5/12#
#sin x = tan x.cos x = (5/12)(12/13) = 5/13#
#cot x = 1/(tan x) = 12/5#
#csc x = 1/(sin x) = 13/5#

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Given #tanx=5/12, secx=13/12# to find the remaining trigonometric function?

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