Given #sintheta=6/11# and #sectheta>0#, how do you find #costheta, tantheta#? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Shwetank Mauria Aug 3, 2017 #costheta=sqrt85/11# and #tantheta=6/sqrt85# Explanation: As #sintheta# and #sectheta# both are positive #theta# lies #Q1# and hence all trigonometricratios of #theta# are positive. #costheta=sqrt(1-sin^2theta)=sqrt(1-(6/11)^2)# #=sqrt(1-36/121)=sqrt(85/121)=sqrt85/11# #tantheta=(6/11)/(sqrt85/11)=6/sqrt85# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 6701 views around the world You can reuse this answer Creative Commons License