Given $sin60^circ=sqrt3/2$ and $cos60^circ=1/2$ , how do you find $cos30^circ$ ?

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Given $sin60^circ=sqrt3/2$ and $cos60^circ=1/2$ , how do you find $cos30^circ$ ?

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Answer 1 · 2016-12-12T16:40:53

$cos(30^@)=sqrt(3)/2$

Explanation:

Based on the image below and the basic definitions of $sin$ and $cos$
we know that $cos(theta)=sin(90^@-theta)$
enter image source here
Therefore $cos(30^@)=sin(60^@)=sqrt(3)/2$

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Given $sin60^circ=sqrt3/2$ and $cos60^circ=1/2$ , how do you find $cos30^circ$ ?

1 Answer

Explanation:

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Given $sin60^circ=sqrt3/2$ and $cos60^circ=1/2$ , how do you find $cos30^circ$ ?