# Given #sin theta = 2/3# and #pi/2<theta<pi#, how do you find the value of the 5 other trigonometric functions?

##### 1 Answer

May 6, 2015

Since sin x > 0 and

sin x = 2/3 -> sin^2 x = 4/9

May 6, 2015

Since sin x > 0 and

sin x = 2/3 -> sin^2 x = 4/9

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