Given secθ=6/5 and tanθ<0, how do you find the values of the other five trigonometric functions?

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Given secθ=6/5 and tanθ<0, how do you find the values of the other five trigonometric functions?

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Answer 1 · 2015-11-02T23:50:08

Find 6 trig function values, knowing sec #x = 6/5# and tan x < 0.

Explanation:

#sec x = 6/5 #--> #cos x = 5/6# --> arc #x = +- 33^@56.#
Since tan x < 0, then #x = -33^@56.#
sin (- 33.56) = - 0.55
#tan (-33.56) = - 0.55/0.83 = - 0.66#
#cot (-33.56) = 1/(tan) = - 1.51#
#sec (-33.56) = 6/5#
#csc (-33.56) = 1/(sin) = 1/-0.55 = -1.82#

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Given secθ=6/5 and tanθ<0, how do you find the values of the other five trigonometric functions?

1 Answer

Explanation:

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