Given $log_b3= 0.5283$ and $log_b5=0.7740$ , how do you find $log_b(5/3)$ ?

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Answer 1 · 2015-07-06T00:56:45

$log_b(5/3) = 0.2457$

Remember that $log_b(x/y) = log_bx -log_by$

So

$log_b(5/3) = log_b5 – log_b3 = 0.7740 - 0.5283$

$log_b(5/3) = 0.2457$

Given log_b3= 0.5283log_b3= 0.5283 and log_b5=0.7740log_b5=0.7740, how do you find log_b(5/3)log_b(5/3)?