Given #log_b3= 0.5283# and #log_b5=0.7740#, how do you find #log_b(5/3)#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Ernest Z. Jul 6, 2015 #log_b(5/3) = 0.2457# Explanation: Remember that #log_b(x/y) = log_bx -log_by# So #log_b(5/3) = log_b5 – log_b3 = 0.7740 - 0.5283# #log_b(5/3) = 0.2457# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 2236 views around the world You can reuse this answer Creative Commons License