Given $f (x) = 7 x^{2} - 5 x$ $f(x) = 7x^2 - 5x$ , $g (x) = 17 x - 4$ $g(x) = 17x - 4$ how do you find (fog)(6)?

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Given $f (x) = 7 x^{2} - 5 x$ $f(x) = 7x^2 - 5x$ , $g (x) = 17 x - 4$ $g(x) = 17x - 4$ how do you find (fog)(6)?

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Answer 1 · 2018-05-16T12:28:47

$(f \circ g) (6) = 66, 738$ $(fcircg)(6)=66,738$

Explanation:

$(f \circ g) (x)$ $(fcircg)(x)$ can be written as $f (g (x))$ $f(color(blue)(g(color(red)x)))$

If $g (x) = 17 x - 4$ $color(blue)(g(color(red)x))=17color(red)x-4$
then $g (6) = 17 \cdot 6 - 4 = 98$ $color(blue)(g(color(red)6))=17 * color(red)6 -4 = color(blue)(98)$

and if $(f o g) (x) = f (x) = 7 x^{2} - 5 x$ $(fog)(color(blue)x)=f(color(blue)x)=7color(blue)x^2-5color(blue)x$
then $(f o g) (x) = f (g (x)) = 7 {g (x)}^{2} - 5 g (x)$ $(fog)(color(blue)x)=f(color(blue)(g(color(red)x)))=7color(blue)(g(color(red)x))^2-5color(blue)(g(color(red)x))$
and
$then (f \circ g) (x) = f (g (6)) = 7 \cdot 98^{2} - 5 \cdot 98 = 66738$ $color(white)("then ")(fcircg)(color(blue)x)=f(color(blue)(g(color(red)6)))=7 * color(blue)(98)^2 - 5 * color(blue)(98)=66738$
(I used a calculator for the last evaluation)

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Given $f (x) = 7 x^{2} - 5 x$ $f(x) = 7x^2 - 5x$ , $g (x) = 17 x - 4$ $g(x) = 17x - 4$ how do you find (fog)(6)?

1 Answer

Explanation:

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Given f(x) = 7x^2 - 5xf(x)=7x2−5xf(x) = 7x^2 - 5x, g(x) = 17x - 4g(x)=17x−4g(x) = 17x - 4 how do you find (fog)(6)?

1 Answer

Explanation:

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Given $f (x) = 7 x^{2} - 5 x$ $f(x) = 7x^2 - 5x$ , $g (x) = 17 x - 4$ $g(x) = 17x - 4$ how do you find (fog)(6)?