Given #f(x)=2(3x+4)-6#, how do you find the y intercept?

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Answer 1 · 2018-05-08T04:53:48

Simplify the equation to get #6x+2#, meaning the #y#-int. is #(0,2)#.

The equation in the question has not yet been simplified down yet. We want to get it into slope-intercept form, or

#y=mx+b#

So we multiply out #2(3x+4)# and get

#y = 6x+8 - 6#

Now we add in the #-6# and our equation should look like

#y=6x+8-6#

We know that #8-6# is #2#, so our #b# value, i.e. the #y#-intercept, is #2# and #m# (the slope) is #6#.

The final product should look like:

#y=6x+2#

Hence, the #y#-intercept is #(0,2)#.

Hope this helped.