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Given #A=((-1, 2), (3, 4))# and #B=((-4, 3), (5, -2))#, how do you find 3A?

1 Answer

Apr 28, 2016

#3A=((-3,6),(9,12))#

Explanation:

If #k# is a constant and #M=((m_(11),...,m_(c1)),(...,...,...),(m_(r1),...,m_(rc)))# is a matrix

then
#color(white)("XXX")k*M=((k*m_(11),...,k*m_(c1)),(...,...,...),(k*m_(r1),...,k*m_(rc)))#

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