Given relationship: #color(green)(y=1/3x" "...Equation(1)#
We will also need #x="something"# so lets deal with that
Multiply both sides by #color(red)(3)#. This will turn the #1/3# from #1/3x# into 1. I am doing this because #1xx x =x#
#color(green)(y=1/3xx x color(white)("dddd")->color(white)("dddd")ycolor(red)(xx3)color(white)("d")=color(white)("d")1/3color(red)(xx3)xx x)#
#color(green)(color(white)("dddddddddddd.")->color(white)("dddddd")3y color(white)("d")= color(white)("d")color(red)(3)/3xx x#
#color(green)(color(white)("dddddddddddd.")->color(white)("dddddd.")3ycolor(white)("d")=color(white)("d")x" ".....Equation(2)#
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#color(blue)("Consider the pair "(x,y)->(color(red)(-3),y_1))#
Need to determine #y_1# so using #Eqn(1)#
#color(green)(y=1/3x color(white)("ddd")->color(white)("ddd")y= 1/3xx color(red)((-3))) #
#color(green)( color(white)("ddddddddd")->color(white)("ddd")y=-1)#
#color(white)("dddddd")color(blue)( (-3,y_1)->(-3,-1) )#
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#color(blue)("Consider the pair "(x,y)->(color(red)(0),y_2))#
Need to determine #y_2# so using #Eqn(1)#
#color(green)(y=1/3x color(white)("ddd")->color(white)("ddd")y= 1/3xx color(red)((0))) #
#color(green)( color(white)("ddddddddd")->color(white)("ddd")y=0)#
#color(white)("dddddd")color(blue)( (0,y_2)->(0,0 ) )#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Consider the pair "(x,y)->(x_1,color(red)(3),))#
Need to determine #x_1# so using #Eqn(2)#
#color(green)(3y=x_1 color(white)("ddd")->color(white)("ddd")3xxcolor(red)(3)= x_1) #
#color(green)( color(white)("ddddddddd")->color(white)("ddd")x_1=9)#
#color(white)("dddddd")color(blue)( (x_1,3)->(9,3) )#
