Find (d^2y)/(dx^2)∣_[(x,y)=(2,1)] if y is a differentiable function of x satisfying the equation x^3+2y^3 = 5xy? Plot it?

1 Answer
May 29, 2016

125/16

Explanation:

Taking the derivative of x^3+2y^3=5xy with respect to x, we see that

3x^2+6y^2dy/dx=5y+5xdy/dx

Rearranging and solving for dy/dx shows that

dy/dx=(5y-3x^2)/(6y^2-5x)

Note that

(dy)/(dx)∣_[(x,y)=(2,1)]=(5-12)/(6-10)=7/4

Differentiating once more:

(d^2y)/dx^2=((5ydy/dx-6x)(6y^2-5x)-(12ydy/dx-5)(5y-3x^2))/(6y^2-5x)^2

When evaluating this at (2,1), each instance of dy/dx becomes 7/4.

(d^2y)/dx^2|_[(x,y)=(2,1)]=((5(7/4)-12)(6-10)-(12(7/4)-5)(5-12))/(6-10)^2

(d^2y)/dx^2|_[(x,y)=(2,1)]=((-13/4)(-4)-16(-7))/16

(d^2y)/dx^2|_[(x,y)=(2,1)]=(13+112)/16=125/16