Estimate the number of moles of solute present in each of the following solutions 256 mL of 0.358 M Ca(NO3)2 and 4 liters of 0.516 M HBr??

1 Answer
anor277
Jul 31, 2017

By definition, #"concentration"="moles of solute"/"volume of solution"#

Explanation:

And thus #"moles of solute"# is given by the product #"volume"xx"concentration"#......

For the #Ca(NO_3)_2(aq)# solution, we has........

#256*mLxx10^-3*L*mL^-1xx0.358*mol*L^-1=0.0917*mol# WITH RESPECT TO #"calcium nitrate"#

And for the #HBr(aq)# solution, we has........

#4.00*Lxx0.516*mol*L^-1=2.064*mol# WITH RESPECT TO #"hydrobromic acid"#......

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