Determine the molarity and nomality of the aqueous solution containing 100g of Al2(SO4)2?

1 Answer
anor277
Aug 6, 2017

#"Molarity"="Moles of solute"/"Volume of solution"#

Explanation:

Now #"moles of solute"=(100*g)/(342.15*g*mol^-1)=??*mol#

But we ain't got a volume of solvent specified........so we cannot proceed......

And by the way #"aluminum sulfate"# is #Al_2(SO_4)_3#, the salt of #Al^(3+)# and #SO_4^(2-)# ions..........

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