Could i have some help please ??

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2 Answers
May 22, 2018

Well, we can tell you the molar quantity associated with 1*g of sucrose...

Explanation:

"Number of moles"="mass of stuff"/"molar mass of substance"

(1.00*g)/(underbrace(342.30* g*mol^-1)_"molar mass of sucrose")=2.92xx10^-3*mol

May 22, 2018

0.002 92 mol sucrose; 0.003 90 mol palmitic acid

Explanation:

Moles of sucrose

The formula of sucrose is "C"_12"H"_22"O"_11.

"M_text(r) = 342.30

"Moles of sucrose" = 1.00 color(red)(cancel(color(black)("g sucrose"))) × "1 mol sucrose"/(342.30 color(red)(cancel(color(black)("g sucrose")))) = "0.002 92 mol sucrose"

Moles of palmitic acid

The formula of palmitic acid is "C"_16"H"_32"O"_2.

"M_text(r) = 256.42

"Moles of palmitic acid" = 1.00 color(red)(cancel(color(black)("g palmitic acid"))) × "1 mol palmitic acid"/(256.42 color(red)(cancel(color(black)("g palmitic acid")))) = "0.003 90 mol palmitic acid"