Could any one tell me how to solve this equation? Thanks :)

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Answer 1 · 2016-11-10T20:45:41

$x = 42/55$

$3 x/2+ 7 2/3x+2=24/2-x" "larr$ change to improper fractions

$(6+x)/2 + (23x)/3 +2 = 12-x" "larr xx 6$

$(cancel6^3xx(6+x))/cancel2 + (cancel6^2xx(23x))/cancel3 +6xx2 = 6xx12-x xx6$

$18+3x + 46x +12 =72 -6x$

$49x+6x = 72-18-12$

$55x = 42$

$x = 42/55$