Container A holds 737 mL of ideal gas at 2.30 atm. Container B holds 114 mL of ideal gas at 4.40 atm. lf the gases are allowed to mix together, what is the resulting pressure?

According to Dalton's Law of Partial Pressures, each gas will exert its pressure independently of the other.

Hence we can use Boyle's Law to calculate the pressure of each gas separately as it expands into the total volume of the two containers.

Calculate the pressure of Gas A

Boyle's Law is

#color(blue)(bar(ul(|color(white)(a/a)p_1V_1 = p_2V_2color(white)(a/a)|)))" "#

#p_1 = "2.30 atm"; color(white)(l)V_1= "737 mL"#
#p_2 = "?";color(white)(mmmm) V_2 = "737 mL + 114 mL" = "851 mL"#

#p_2 = p_1 × V_1/V_2 = "2.30 atm" × (737 color(red)(cancel(color(black)("mL"))))/(851 color(red)(cancel(color(black)("mL")))) = "1.992 atm"#

Calculate the pressure of Gas B

#p_1 = "4.40 atm"; color(white)(l)V_1= "114 mL"#
#p_2 = "?";color(white)(mmmm) V_2 = "114 mL + 737 mL" = "851 mL"#

#p_2 = p_1 × V_1/V_2 = "4.40 atm" × (114 color(red)(cancel(color(black)("mL"))))/(851 color(red)(cancel(color(black)("mL")))) = "0.5894 atm"#

Calculate the total pressure

The formula for Dalton's Law of Partial Pressures is

#color(blue)(bar(ul(|color(white)(a/a)p_"tot" = p_"A" + p_"B"color(white)(a/a)|)))" "#

#p_"tot" = "1.992 atm + 0.5894 atm" = "2.58 atm"#