Consider the function f(x)=1/sqrt(x+2) on the interval [-1, 23], how do you find the average or mean slope of the function on this interval?

1 Answer
May 12, 2017

The mean slope is =-1/30

Explanation:

The mean slope of a function f(x) over an interval [a,b] is

=(f(b)-f(a))/(b-a)

Here,

f(x)=1/sqrt(x+2)

f(-1)=1/sqrt(-1+2)=1

f(23)=1/sqrt(23+2)=1/5

Therefore,

the mean slope is

=(f(23)-f(-1))/(23-(-1))

=(1/5-1)/(24)

=-4/5*1/24=-1/30