# Calculate the volume in milliliters of 2.35 M potassium hydroxide that contains 13.5 g of solute?

##### 1 Answer

Once you work out the keywords, the math isn't too bad. First, let's define some terms:

#"Molarity" = "mols solute"/"L solution" = "M" = "mols"/"L"# #"Solute" = "KOH" -= "potassium hydroxide"# #"Solvent" = "H"_2"O"# (water)

You are asked to get the

So, this is asking you to use the molarity and do a unit conversion. Since you want the *volume* for your answer, you would start with the orientation of the fraction *so that the volume starts on top*.

#"L"/(2.35 cancel"mols") xx cancel"1 mol KOH"/(56.1056 cancel"g KOH") xx 13.5 cancel"g KOH"#

#=# #"0.1024 L solution"#

But since you were asked for this in

#color(blue)(V_(sol n)) = 0.1024 cancel"L" xx "1000 mL"/cancel"L"#

#=# #color(blue)("102.4 mL solution")#

For perspective, in real life, a