Assume y varies inversely as #x," if " y=7 " when " x=6#, how do you find y when #x=-12#?

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Answer 1 · 2017-07-29T14:42:52

#y = -3.5#

Write the information as in inverse proportion first.

#y prop 1/x#

Make an equation by multiplying by the constant #k#

#y = k/x" "rArr k = xy#

Find the value for #k# from the information given.

#k = 6 xx7 = 42#

#:. y= 42/x#

Now find the required value of #y#:

#y = 42/-12#

#y = -3.5#