Assume that 7 people, including the husband and wife pair, apply for 6 sales positions. People are hired at random. What is the probability that one is hired and one is not?

1 Answer
Jun 27, 2016

#2/7#

Explanation:

I assume that "one is hired and one is not" means any one of them is hired.

The no of ways 6 people can be hired from 7 at random is #""^7C_6=7#

Among these 7 groups there exist 2 groups where either husband or wife is present.

So number of favorable events is 2 and no of possible events is 7.

Hence the probability one is hired and one is not wil be

#P="no of favorable events"/"no of possible events"#

#=2/7#