An ellipsoid has radii with lengths of $8$ , $7$ , and $9$ . A portion the size of a hemisphere with a radius of $8$ is removed form the ellipsoid. What is the remaining volume of the ellipsoid?

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An ellipsoid has radii with lengths of $8$ , $7$ , and $9$ . A portion the size of a hemisphere with a radius of $8$ is removed form the ellipsoid. What is the remaining volume of the ellipsoid?

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Answer 1 · 2018-07-14T00:26:08

$1038.82\ \text{unit}^3$

Explanation:

The remaining volume of the ellipsoid will be equal to the difference of volume of original ellipsoid with radii $a=8$ , $b=7$ & $c=9$ & the volume of hemi-sphere of radius $r=8$ hence the remaining volume of ellipsoid

$\frac{4\pi}{3}abc-2/3\pir^3$

$=\frac{4\pi}{3}(8)(7)(9)-2/3\pi(8)^3$

$=\frac{992\pi}{3}$

$=1038.82\ \text{unit}^3$

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An ellipsoid has radii with lengths of $8$ , $7$ , and $9$ . A portion the size of a hemisphere with a radius of $8$ is removed form the ellipsoid. What is the remaining volume of the ellipsoid?

1 Answer

Explanation:

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An ellipsoid has radii with lengths of 8 8 , 7 7 , and 9 9 . A portion the size of a hemisphere with a radius of 8 8 is removed form the ellipsoid. What is the remaining volume of the ellipsoid?

1 Answer

Explanation:

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An ellipsoid has radii with lengths of $8$ , $7$ , and $9$ . A portion the size of a hemisphere with a radius of $8$ is removed form the ellipsoid. What is the remaining volume of the ellipsoid?