An aqueous solution has a mass of 490 grams containing 8.5 xx 10^"-3" gram of calcium ions. What is the concentration of calcium ions in this solution?

1 Answer
Jun 7, 2017

"17 ppm"

Explanation:

Judging by the values you have, the most helpful concentration that can be calculated here is that in parts per million, ppm.

A solution's ppm concentration tells you the number of grams of solute present for every

10^6 = 1,000,000

grams of solution. Now, notice that you can approximate the mass of the solution, which is equal to

"mass solution" = "490 g" + "0.0085 g"

"mass solution = 490.0085 g"

to be equal to the mass of water, the solvent.

"490.0085 g " ~~ " 490 g"

You can thus say that, in your case, a "1 ppm" solution will contain "1 g" of calcium cations for every 10^6 "g" of water.

Use the known composition of the solution as a conversion factor to calculate the number of grams of calcium cations present in 10^6 "g" of solution.

10^6 color(red)(cancel(color(black)("g solution"))) * (8.5 * 10^(-3)color(white)(.)"g Ca"^(2+))/(490color(red)(cancel(color(black)("g solution")))) = "17.35 g Ca"^(2+)

Since this represents the number of grams of calcium cations present in 10^6 "g" of solution, you can say that the solution's ppm concentration is

color(darkgreen)(ul(color(black)("concentration" = "17 ppm Ca"^(2+))))

The answer is rounded to two sig figs, the number of sig figs you have for your values.