We want to find the quotient: "mass of ammonia"/"mass of solution"xx100%mass of ammoniamass of solution×100%.
We know (i) that "moles of ammonia"/"volume of solution"moles of ammoniavolume of solution == 6.00*mol*L^-16.00⋅mol⋅L−1.
We know (ii) that "mass of solution"/"volume of solution"mass of solutionvolume of solution == 0.950*g*mL^-10.950⋅g⋅mL−1.
From (i) we know that a 1*L1⋅L volume of solution contains:
1*Lxx6.00*mol*L^-1xx17.03*g*mol^-11⋅L×6.00⋅mol⋅L−1×17.03⋅g⋅mol−1 == 102.18*g" ammonia"102.18⋅g ammonia
From (ii) we know that, 1*L1⋅L of solution has a mass of 0.950*g*mL^-1xx1000*mL0.950⋅g⋅mL−1×1000⋅mL == 950.0*g950.0⋅g.
And thus "mass of ammonia"/"mass of solution"xx100%mass of ammoniamass of solution×100% ==
(102.18*g)/(950*g)xx100%~=11%102.18⋅g950⋅g×100%≅11% Whewww, arithmetic!!
