Ammonia gas is synthesized according to the balanced equation below. N2 (g) + 3 H2 (g) → 2 NH3 (g) If 2.75 L N2 react with 7.75 L H2, what is the theoretical yield (in liters) of NH3?

Volumes of reactants and products are assumed to be measured at the same temperature and pressure.

(Should I convert the liters into grams to determine theoretical yield or should I leave them as they are?)

1 Answer
P dilip_k
Jan 16, 2017

The balanced equation of the gaseous reaction given is

#N_2(g)+3H_2(g)->2NH_3(g)#

As per the reaction stochiometry we see that the gaseous ractants and products are in the following mole ratio #1:3:2# So ratio of their volume will also follow same ratio.

Hence to maintain that ratio the #2.75L" " N_2(g)# will react with #8.25L" " H_2(g)# to form theoretically #2*2.75L=5.50L" "NH_3(g)#
But the volume of #H_2(g)# will fall short then.So hydrogen given will be fully consumed and the yeild of #NH_3(g)# to be calculated on the consumption of of available #H_2(g) i.e.7.75L#

Si theoretical yeild of #NH_3(g)# will be #=2/3xx7.75L~~5.17L#

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