A wheel rotating with a uniform acceleration covers 100 revolution in the first 10 seconds after the start. What is the angular velocity at the end of 10 seconds?

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Answer 1 · 2018-05-02T13:34:17

The angular velocity is #=125.7rads^-1#

The angle covered is #theta=n*2pi=100xx2pi=200pirad#

The time is #t=10s#

The initial angular velocity is #omega_0=0rads^-1#

Let the angular acceleration be #=alpha rads^-2#

Apply the equation

#theta=omega_0t+1/2alphat^2#

#200pi=1/2alphaxx100#

#alpha=4pirads^-2#

Apply the equation

#omega(t)=omega_0+alphat#

#omega(10)=0+4pixx10=40pirads^-1#

The angular velocity is #=125.7rads^-1#