A wheel rotating with a uniform acceleration covers 100 revolution in the first 10 seconds after the start. What is the angular velocity at the end of 10 seconds?

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Answer 1 · 2018-05-02T13:34:17

The angular velocity is $=125.7rads^-1$

The angle covered is $theta=n*2pi=100xx2pi=200pirad$

The time is $t=10s$

The initial angular velocity is $omega_0=0rads^-1$

Let the angular acceleration be $=alpha rads^-2$

Apply the equation

$theta=omega_0t+1/2alphat^2$

$200pi=1/2alphaxx100$

$alpha=4pirads^-2$

Apply the equation

$omega(t)=omega_0+alphat$

$omega(10)=0+4pixx10=40pirads^-1$

The angular velocity is $=125.7rads^-1$