A voltaic cell which is constructed with Sn+2/Sn (Ereduction=-0.14V) and Zn+2/Zn (Eoxidation=-0.76V) is represented by Zn|Zn+2(1M)||Sn+2|Sn(1M). What is the emf of the cell?

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A voltaic cell which is constructed with Sn+2/Sn (Ereduction=-0.14V) and Zn+2/Zn (Eoxidation=-0.76V) is represented by Zn|Zn+2(1M)||Sn+2|Sn(1M). What is the emf of the cell?

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Answer 1 · 2017-04-22T21:53:29

$E_{cell} = +0.62 V$ $E_text(cell) = "+0.62 V"$

Explanation:

To answer this question, we determine the standard potential of the voltaic cell using the two half-cell potentials.

$m m m m m m m m m m m m m m m m m m m m m m m m m m m E^{\circ} /V$ $color(white)(mmmmmmmmmmmmmmmmmmmmmmmmmmm)E^@"/V"$
Anode: $m 1 \times [Zn(s) \to {Zn}^{2+} (aq) + {2e}^{-}] m m m m m m m l +0.76$ $color(white)(m)1×["Zn(s)" → "Zn"^"2+""(aq)" + "2e"^"-"]color(white)(mmmmmmml)"+0.76"$
Cathode: $1 \times [{Sn}^{2+} (aq) + {2e}^{-} \to Sn(s)] m m m m m m m m -0.14$ $1×["Sn"^"2+""(aq)" +"2e"^"-" → "Sn(s)"]color(white)(mmmmmmmm)"-0.14"$
Cell: $m m m m l l Zn(s) + {Sn}^{2+} (aq) \to {Zn}^{2+} (aq) + Sn(s) m +0.62$ $color(white)(mmmmll)"Zn(s)" + "Sn"^"2+""(aq)" →"Zn"^"2+""(aq)" + "Sn(s)"color(white)(m)"+0.62"$

$E_{cell}^{\circ} = +0.62 V$ $E_text(cell)^@ = "+0.62 V"$

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A voltaic cell which is constructed with Sn+2/Sn (Ereduction=-0.14V) and Zn+2/Zn (Eoxidation=-0.76V) is represented by Zn|Zn+2(1M)||Sn+2|Sn(1M). What is the emf of the cell?

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Explanation:

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