A triangle with angles of A=38, B=83 and C=59. Side opposite to angle C is measuring 20. How do you find lengths of other sides?

1 Answer
Aug 2, 2016

Use the Law of Sines to get
a=14.365, b=23.151

Explanation:

Given a triangle with angles A, B, C and corresponding opposite side lengths a, b, c
Law of Sines:
color(white)("XXX")a/(sin(A))=b/(sin(B))=c/(sin(C))

with the given data values
color(white)("XXX")a/sin(38^@)=b/sin(83^@)=20/sin(59^@)

rArr
color(white)("XXX")a=sin(38^@)*20/sin(59^@) ~~14.36502
and
color(white)("XXX")b=sin(83^@)*20/sin(59^@)~~23.15075

...The above is based on use of a calculator and the assumption that I didn't making typos in my data entry.