A triangle has corners at (2 ,7 ), (3 ,1 ), and (8 ,9 ). What is the area of the triangle's circumscribed circle?

1 Answer
Oct 19, 2016

Area of inscribed circle is (approx.) 9.5096 (sq.units)

Explanation:

If A=(2,7), B=(3,1), and C=(8,9)
then
color(white)("XXX")abs(AB)=sqrt((3-2)^2+(1-7)^2)=sqrt(37)~~6.0828
color(white)("XXX")abs(BC)=sqrt((8-3)^2+(9-1)^2)=sqrt(89)~~9.4340
color(white)("XXX")abs(CA)=sqrt((2-8)^2+(7-9)^2)=sqrt(40)~~6.3246

The perimeter,p_trianglem of the triangle is
color(white)("XXX")"p_triangle=abs(AB)+abs(BC)+abs(CA)~~21.8413

The semi-perimeter< s_triangle, of the triangle is
color(white)("XXX")s_triangle = (p_triangle)/2~~10.9207

The area of the triangle, "area"_triangle can be calculated geometrically or using Heron's Formula:
color(white)("XXX")"area"_triangle = sqrt(s(s-a)(s-b)(s-c))~~19

The radius, r_circ of a circle inscribed in a triangle is given by the formula
color(white)("XXX")r_circ=("area"_triangle)/s ~~ 19/10.9207 ~~1.7398

The area, "area"_circ, of a circle inscribed in a triangle is given by the formula
color(white)("XXX")"area"_circ = pi * r_circ ^2 ~~9.5096