A titration neutralizes 25mL of an unknown acid using 32 mL of 6.0 M KOH. What is the molarity of the unknown acid in the original solution? Chemistry Solutions Molarity 1 Answer Doc048 Apr 30, 2017 #[(Molarity Acid)(Volume Acid)] = [(Molarity Base)(Volume Base)]# Explanation: #(Molarity Acid)(25 ml) = (6.0M)(32ml)# #Molarity Acid = [(6.0M)(32ml)]/[(25ml)] = 7.68M# Answer link Related questions what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... How can molarity and osmolarity be calculated from mass per unit volume? How can molarity be used as a conversion factor? How high can molarity be? How does molarity change with temperature? How do you find molarity of a solution? What is the molarity of 10 NaOH? What is the molarity of 3 hydrogen peroxide? What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? What is molarity? See all questions in Molarity Impact of this question 1505 views around the world You can reuse this answer Creative Commons License