A solution of potassium fluoride turns litmus paper blue. What are the products of the modified Arrhenius net ionic equation for this compound? Question options: ~H2O ~F ~HF ~H3O+ ~HKF+ ~OH

1 Answer
May 28, 2017

F+H2O(l)HF(aq)+H2O(l)

Explanation:

HF is a WEAK acid in aqueous solution.......i.e.

HF(aq)+H2O(l)F+H3O+

Ka=103.17=6.76×104.

If we describe something as a weak acid, we might also describe its conjugate base as reasonably strong in that it competes for the proton effectively. Fluoride thus gives rise to a basic solution, and this is in contrast to the solution behaviour of HCl, HBr, HI, for which in aqueous solution, the equilibrium LIES strongly to the right.

HX(aq)+H2O(l)X+H3O+
XF,X=Cl,Br,I

And thus while Cl, Br, and I ARE WEAK Bronsted bases, F, being smaller and more charge dense, is a moderately strong Bronsted base.