A solution of H_2SO_4(aq)H2SO4(aq) with a molal concentration of 3.58 m has a density of 1.200 g/mL. What is the molar concentration of this solution?
1 Answer
"3.18 M"3.18 M
Knowing the molal concentration, here is what you know... by assuming
"3.58 mols H"_2"SO"_43.58 mols H2SO4
"1 kg water"1 kg water
By using the density of the solution, along with the mass of the solution, we can get the volume of the solution. Then, by definition, the molarity is
m_(soln) = 3.58 cancel("mols H"_2"SO"_4) xx ("98.079 g H"_2"SO"_4)/cancel("1 mol H"_2"SO"_4) + cancel"1 kg water" xx "1000 g"/cancel"1 kg"
= 1.35_(112282) xx 10^(3) "g soln"
Therefore, its volume is:
1.35_(112282) xx 10^(3) cancel"g soln" xx cancel"1 mL soln"/(1.200 cancel"g soln") xx "1 L soln"/(1000 cancel"mL soln")
= 1.12_(5935683) "L soln"
Therefore, its molar concentration is:
("3.58 mols H"_2"SO"_4)/(1.12_(5935683) "L soln")
= color(blue)("3.18 M")
