A solution of concentration 5 x 10^-5 M has absorbance of 0.75 in a cell of 1 cm length. Calculate molar absorptivity and transmittance of the cell?

1 Answer
Feb 14, 2016

(a)

1.5xx10^(4)"L/mol/cm".

(b)

17.8%

Explanation:

(a)

The Beer - Lambert Law gives us:

A=epsilon_(@)cl

:.epsilon_(@)=(A)/(cl)

:.epsilon_(@)=(0.75)/(5xx10^(-5)xx1)

epsilon_(@)=1.5xx10^(4)"L/mol/cm"

(b)

log(I_0/I)=0.75

Since I_0=100rArr

2-logI=0.75

I=17.8% which is the transmittance.