A solution is prepared from 8 grams of acetic acid (CH_2CO_2H) and 725 grams of water. What is the molarity of this solution?

1 Answer
anor277
Aug 15, 2016

"Molarity" = "Moles of solute"/"Volume of solution"

Explanation:

"Molarity" = ((8*g)/(60.05*g*mol^-1))/(0.725*L) ~= 0.18*mol*L^-1.

Note that I have assumed here that the volume of the acid in the given mass of water is not going to vary substantially from 0.725*L, which was the standard volume of the mass of water used to dilute it. This is a reasonable assumption.

If we liked, we could calculate the "molality" of the solution:

"Moles of solute"/"kg of solvent".

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