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A solution contains 0.063 g of oxalic acid, #H_2C_2O_4 * 2H_2O#, in 250 mL. What is the molarity of this solution?

1 Answer

Jul 7, 2016

#"Molarity"# #~=# #2xx10^-3*mol*L^-1#

Explanation:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

#=# #(0.063*g)/(126.07*g*mol^-1)xx1/(0.250*L)# #=# #??*mol*L^-1#

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