A solid consists of a cone on top of a cylinder with a radius equal to the cone. The height of the cone is $6$ and the height of the cylinder is $5$ . If the volume of the solid is $20 pi$ , what is the area of the base of cylinder?

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Answer 1 · 2017-12-23T07:32:13

The area of the base is $=8.98u^2$

The volume of a cone is

$V_(co)=1/3pir^2h_(co)$

The radius is $=r$

The height of the cone is $h_(co)=6$

The volume of a cylinder is

$V_(cy)=1/3pir^2h_(cy)$

The radius is $=r$

The height of the cone is $h_(cy)=5$

The volume of the solide is $=20pi$

$1/3a*6+a*5=20pi$

$a(1/3*6+5)=7a=20pi$

The area of the base is

$a=20/7pi=8.98u^2$

A solid consists of a cone on top of a cylinder with a radius equal to the cone. The height of the cone is 6 6 and the height of the cylinder is 5 5 . If the volume of the solid is 20 pi20 pi, what is the area of the base of cylinder?