A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $27$ and the height of the cylinder is $36$ . If the volume of the solid is $420 pi$ , what is the area of the base of the cylinder?

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $27$ and the height of the cylinder is $36$ . If the volume of the solid is $420 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2016-03-27T15:08:29

Volume of solid $V = Axxh_(cy)+1/3xxAxxh_(co)$
Where
Area of cylnder = area of cone = A
Height of cylinder = $h_(cy)=36$
Height of cone = $h_(co)=27$
Volume of the solid $V=420pi$
$:. 18pi= Axx36+1/cancel3xxAxxcancel27^9=45A$
$:. A= (420pi)/45=28/3pi$

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $27$ and the height of the cylinder is $36$ . If the volume of the solid is $420 pi$ , what is the area of the base of the cylinder?

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 27 27 and the height of the cylinder is 36 36 . If the volume of the solid is 420 pi420 pi, what is the area of the base of the cylinder?

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $27$ and the height of the cylinder is $36$ . If the volume of the solid is $420 pi$ , what is the area of the base of the cylinder?