A sequence is defined by the recursive function $f(n+1) = f(n) - 2$ . If $f(1) = 10$ , what is $f(3$ )?

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Answer 1 · 2018-03-20T14:00:02

$f(3)=6$

we have

$f(n+1)=f(n)-2$

and

$f(1)=10$

to find

$f(3)$

$f(2)=f(1)-2=10-2=8$

$f(3)=f(2)-2=8-2=6$

A sequence is defined by the recursive function f(n+1) = f(n) - 2 f(n+1) = f(n) - 2 . If f(1) = 10 f(1) = 10 , what is f(3 f(3 )?