A rectangle is 5 cm longer than it is wide. If the length and width are both increased by 3 cm, its area is increased by 60 cm2. How do you find the dimensions of the original rectangle?

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Answer 1 · 2016-11-08T15:01:41

Let the width be #x# and the length #x + 5#.

#l xx w = A#

#(x + 3)(x + 5 + 3) = x(x + 5) + 60#

#(x + 3)(x + 8) = x^2+ 5x + 60#

#x^2 + 3x + 8x + 24 = x^2 + 5x + 60#

#6x = 36#

#x = 6#

Hence, the width of the original rectangle was #6# and the length was #11#.

Hopefully this helps!