A quasar consumes 1 solar mass of material per year, converting 15 percent of it directly into energy. What is the quasar's luminosity, in solar units?

1 Answer
Feb 1, 2016

L = 1.478 xx 10^13 L_o.

Explanation:

![http://www.eso.org/public/usa/images/eso1122a/](useruploads.socratic.org)

Quasars are created as a result of mas being swallowed by the supermassive black hole at the center of an active galactic nucleus. The luminosity of a quasar is the rate at which energy is emitted by the quasar. We are given the rate of 1 M_o. "/ yr", and Einstein gave us the formula to convert mass into energy.

E=mc^2

Here, m is the mass converted and c is the speed of light. One solar mass is equal to 1.989 xx 10^30"kg". Using the mass conversion formula;

E = (1.989xx10^30"kg")(3 xx 10^8 "m/s")^2

E = 1.790 xx 10^47"J"

Luminosity is measured in watts, "W", or "J/s", so we need to convert years into seconds.

1"year" = 365"days" = 8,760 "hours" = 525,600 "minutes"
= 31,536,000 "seconds"

So the luminosity of the quasar is;

L = (1.790 xx 10^47 "J")/(3.154 xx 10^7 "s") = 5.675 xx 10^39 "W"

For comparison, the luminosity of the Sun is;

L_o. = 3.828 xx 10^26 "W"

Which is about 1 ten-billionth of the luminosity of the quasar.

L = (5.675 xx 10^39"W")/(3.282 xx 10^26"W")=1.478 xx 10^13 L_o.