A gas at 69°C occupies a volume of 0.67 L. At what Celsius temperature will the volume increase to 1.86 L?

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Answer 1 · 2015-03-06T18:57:19

The volume will increase to 1.86 L at 680 °C.

This is a problem involving Charles' Law.

#V_1/T_1 = V_2/T_2#

In your problem,

#V_1 = "0. 67 L"#; #V_2 = 1. 86 L"#
#T_1 = "(69 + 273.15) K" = "342.15 K"#; #T_2 = "?"#

#V_1/T_1 = V_2/T_2#

#T_2 = T_1 × V_2/V_1 = "342.15 K" × "1.86 L"/"0.67 L" = "950 K"# (2 significant figures)

#T_2 = "(950 – 273.15) °C" = "680 °C"#