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A curve is given by the parametric equations: #x=cos(t) , y=sin(2t)#, how do you find the cartesian equation?

1 Answer

Jul 4, 2016

#y^2=4x^2(1-x^2)#

Explanation:

#x = cos(t)->x^2=cos^2(t)#
#y = sin(2t)=2cos(t)sin(t)->y^2=4cos^2(t)sin^2(t)#

but #cos^2(t)+sin^2(t) = 1#

then

#y^2=4x^2(1-x^2)#

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