A crane lifts a 487 kg beam vertically at a constant velocity. If the crane does 5.20 x 10^4 of work on the beam find the vertical distance that it lifted the beam?

Question

I understand the equation that needs to be used to solve the problem. What don't I understand is how does the coefficient of gravity(g) which is 9.8m/s plays a role in this question. Can someone kindly explain this part for me?

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Answer 1 · 2016-05-08T13:03:31

Vertical distance $d=10.9" "$ meters

The only force involve in the crane is the weight $F$ of the beam

The force of the weight
$F=mg$

$F=487" "$ $kg*(-9.8" "m/sec^2")$

$F=-4772.6" "$ Newtons (negative because weight is downward direction)

Force of the crane is equal to weight directed upward (positive) $=+4772.6" "$ Newtons

The work $W=F*d" "$ where $d=$ distance

$d=W/F=(5.2 x 10^4)/4772.6$

$d=10.89552864" "$ meters

God bless....I hope the explanation is useful.