A compound is formed when 9.03 g Mg combines completely with 3.48 g N. What is the percent composition of this compound?

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Answer 1 · 2016-02-20T01:26:24

The composition is #"72.2 % Mg"# and #"27.8 % N"# by mass.

#"% by mass" = "mass of a component"/"total mass" × 100 %#

You have #"9.03 g Mg"# and #"3.48 g N"#, so

#"total mass = (9.03 + 3.48) g = 12.51 g"#

∴ #"% Mg" = (9.03 color(red)(cancel(color(black)("g"))))/(12.51 color(red)(cancel(color(black)("g")))) × 100 % =72.2 %#

#"% N" = (3.48 color(red)(cancel(color(black)("g"))))/(12.51 color(red)(cancel(color(black)("g")))) × 100 % = 27.8 %#

The composition is #"72.2 % Mg"# and #"27.8 % N"# by mass.