A circuit with a resistance of $8 Omega$ has a fuse with a capacity of $5 A$ . Can a voltage of $36 V$ be applied to the circuit without blowing the fuse?

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Answer 1 · 2016-10-09T06:02:32

Current in circuit= voltage divided by Resistance.
36/8= 4.5

Fuse is to blow at 5 amps.Here we get current=4.5..Fuse will not blow. But safety margin is less.

A circuit with a resistance of 8 Omega8 Omega has a fuse with a capacity of 5 A5 A. Can a voltage of 36 V36 V be applied to the circuit without blowing the fuse?