A circuit with a resistance of $8 Omega$ has a fuse with a capacity of $3 A$ . Can a voltage of $45 V$ be applied to the circuit without blowing the fuse?

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A circuit with a resistance of $8 Omega$ has a fuse with a capacity of $3 A$ . Can a voltage of $45 V$ be applied to the circuit without blowing the fuse?

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Answer 1 · 2016-01-23T18:58:29

$No$

Explanation:

Data:-

Resistance $=R=8Omega$

Voltage $=V=45V$

The fuse has capacity of 3A

Sol:-

If we apply voltage $V$ across a resistor whose resistance is $R$ then the current $I$ flowing across it can be calculated by

$I=V/R$

Here we are applying voltage of $45V$ across a $8Omega$ resistor, therefore, the current flowing is

$I=45/8=5.625$ $implies I=5.625A$

Since, the fuse has capacity of $3A$ but the current flowing in the circuit is $5.625A$ therefore, the fuse will melt. Thus, the answer to this question is $No$ .

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A circuit with a resistance of $8 Omega$ has a fuse with a capacity of $3 A$ . Can a voltage of $45 V$ be applied to the circuit without blowing the fuse?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

A circuit with a resistance of 8 Omega8 Omega has a fuse with a capacity of 3 A3 A. Can a voltage of 45 V45 V be applied to the circuit without blowing the fuse?

1 Answer

Explanation:

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Impact of this question

A circuit with a resistance of $8 Omega$ has a fuse with a capacity of $3 A$ . Can a voltage of $45 V$ be applied to the circuit without blowing the fuse?