A circuit with a resistance of $8 Omega$ has a fuse with a capacity of $3 A$ . Can a voltage of $36 V$ be applied to the circuit without blowing the fuse?

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Answer 1 · 2018-05-25T00:24:57

No.

Well, we need to find the voltage that the fuse can hold, so we use Ohm's law, which states that,

$V=IR$

where:

$V$ is the voltage in volts

$I$ is the current in amperes

$R$ is the resistance in ohms

So, we get:

$V=3 \ "A"*8 \ Omega$

$=24 \ "V"$

Since a voltage of $36$ volts is applied to the circuit, but the fuse only holds $24$ volts, it'll blow up the fuse.

A circuit with a resistance of 8 Omega8 Omega has a fuse with a capacity of 3 A3 A. Can a voltage of 36 V36 V be applied to the circuit without blowing the fuse?