A circuit with a resistance of $6 Omega$ has a fuse with a capacity of $5 A$ . Can a voltage of $57 V$ be applied to the circuit without blowing the fuse?

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Answer 1 · 2016-01-05T12:21:57

No, the fuse will blow.

Ohm's Law gives us:

$V=IR$

$:.I=V/R=57/6=9.5"A"$

So you can see that too much current will be drawn through the fuse which is only rated at $6Omega$ so it will blow.

A circuit with a resistance of 6 Omega6 Omega has a fuse with a capacity of 5 A5 A. Can a voltage of 57 V57 V be applied to the circuit without blowing the fuse?