A circuit with a resistance of $3 Omega$ has a fuse with a capacity of $2 A$ . Can a voltage of $9 V$ be applied to the circuit without blowing the fuse?

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Answer 1 · 2016-02-04T15:02:39

No

This require the application of the standard Ohm's Law expression of $V=I*R$ , where $V$ is the voltage, $I$ is the current and $R$ is the resistance

The voltage of $9V$ will generate a current of

$I = V/R = 9/3 =3A$

This will blow the fuse so the answer is No.

A circuit with a resistance of 3 Omega3 Omega has a fuse with a capacity of 2 A2 A. Can a voltage of 9 V9 V be applied to the circuit without blowing the fuse?